我必须编写一个程序,以每行独立的方式读取数字。有没有可能只读取文件中的一行,然后从缓冲区中读取一个 int
,并以此类推直到文件结束?真的很难找到使用读写的好例子。 我的示例有点用,但我想读取直到检测到 '\n'
字符,然后将缓冲区转换为 int。
#include <fcntl.h>
#include <stdio.h>
#include <string.h>
#include <unistd.h>
#include <iostream>
int fd[2];
void readFile(int fd) {
unsigned char buffer[10];
int bytes_read;
int k=0;
do {
bytes_read = read(fd, buffer, 10);
k++;
for(int i=0; i<10; i++) {
printf("%c", buffer[i]);
}
}
while (bytes_read != 0);
}
int tab[50];
int main(int argc, char *argv[]) {
if(argv[1] == NULL || argv[2] == NULL) {
printf("Function requires two arguments!\nGood bye...\n");
return -1;
}
else {
if (access(argv[1], F_OK) == 0) {
fd[0] = open(argv[1], O_RDONLY);
}
else {
fd[0] = open(argv[1], O_WRONLY|O_CREAT|O_SYNC, 0700);
const int size = 50;
for(int i=0; i<size; i++) {
char buf[10];
sprintf(buf, "%d\n", i+1);
write(fd[0], buf, strlen(buf));
}
close(fd[0]);
fd[0] = open(argv[1], O_RDONLY);
if (access(argv[2], F_OK) == 0)
fd[1] = open(argv[2], O_WRONLY);
else
fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);
}
}
if (access(argv[2], F_OK) == 0)
fd[1] = open(argv[2], O_WRONLY);
else
fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);
readFile(fd[0]);
close(fd[0]);
close(fd[1]);
}
修改后的代码:
void readFile(int fd) {
char buffer[10];
int bytes_read;
int k = 0;
do {
char t = 0;
bytes_read = read(fd, &t, 1);
buffer[k++] = t;
printf("%c", t);
if(t == '\n' && t == '\0') {
printf("%d", atoi(buffer));
for(int i=0; i<10; i++)
buffer[i]='\0';
k = 0;
}
}
while (bytes_read != 0);
}
您可以使用 fgets。这里有很好的相关文档:-
http://www.cplusplus.com/reference/cstdio/fgets/
如果您不想使用 fgets,下面的方法也行得通 :-
int readline(FILE *f, char *buffer, size_t len)
{
char c;
int i;
memset(buffer, 0, len);
for (i = 0; i < len; i++)
{
int c = fgetc(f);
if (!feof(f))
{
if (c == '\r')
buffer[i] = 0;
else if (c == '\n')
{
buffer[i] = 0;
return i+1;
}
else
buffer[i] = c;
}
else
{
//fprintf(stderr, "read_line(): recv returned %d\n", c);
return -1;
}
}
return -1;
}